A 2 kN block is resting on a rough horizontal surface for which the coefficient of friction is 0.4. Determine the force P (kilonewton) required to cause motion to impend if applied to the block downward at 40° with the horizontal. (round off to two decimal places)
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∑ F v = 0
Psin40 + 2 = N
∑ F h = 0
Pcos40 = F = 0.4(Psin40 + 2)
1.92P - 0.64P = 2
1.28P = 2
P = 1.56 kN