Force and Laws of Motion

A ship of mass 30,000,000 kg initially at rest is pulled by a force of 50,000 N through a distance of 3 m. Assume that the resistance due to water is negligible, find the speed of the ship in m/s.


The answer is 0.1.

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2 solutions

We have ; m=3,00,00,000kg F=50,000 s=3m we know ,a=F/m =1/600m/s^2 now using , v^2 = u^2 + 2as , we get , v^2 = 0 + 2 * 1/600*3 v^2 = 1/100 v = 1/10 = 0.1 m/s

Ameya Ballal
Sep 2, 2014

f=ma, a=f/m 50000/30000000=a v= 2 3 1/600

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