Basic EM, Ez for you

Two identical solenoids of length L L are separated by distance L L away and the orientations (B direction) of the solenoid are the same and perpendicular to the distance of separation. This cause an interaction force of magnitude F F . Now, if the separation distance becomes 2 L 2L , the force change to x F xF . Determine the value of x x up to 3 decimal points! include the sign in your answer (minus sign means attraction otherwise repulsion)! Assume that the radius of the solenoid is much smaller than its length and the distance between coils are much smaller to its radius.


The answer is 0.110.

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1 solution

Gerry Dunda
Feb 27, 2018

First, we notice that the radius of the solenoid is smaller than its length and the distance between the coils are smaller than its radius. This means that we can think of the solenoid as the collection of many magnetic dipoles aligned in the vertical line. Because head and tail are canceling each other, the net effect is just two monopoles with a different sign but the same magnitude at each end of it.

The equivalent orientation of the solenoids implies that we can think of another system consisted of 4 monopoles (let's choose 2 + monopoles on above others on below) in each rectangular vertex with dimension d × L d \times L where d d is the separation distance. The magnetic field by a monopole can be written as

B = μ 0 q m 4 π r 3 r \vec {B} = \frac {\mu_0 q_m}{4\pi r^3} \vec {r}

where q m q_m is the magnitude of the monopole that depends on the current and internal geometry of the solenoid.

The force exerted on a monopole is given as

F = q m B \vec {F} = q_m \vec {B}

So, by vector analysis, one obtains that this type of force is REPULSION and the magnitude is

F = μ 0 q m 2 π [ 1 d 2 d ( d 2 + L 2 ) 3 / 2 ] F = \frac {\mu_0 q_m}{2\pi}[\frac {1}{d^2} - \frac{d}{(d^2+L^2)^{3/2}}]

By substitution of two cases and take the ratio, we get

x = 1 / 4 2 5 3 / 2 1 1 2 3 / 2 0.110 x = \frac {1/4 - \frac {2}{5^{3/2}}}{1- \frac {1}{2^{3/2}}} \approx 0.110

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