Force digits to number.

Logic Level 2

2 0 1 8 \large {\color{#D61F06}2}\quad {\color{#3D99F6}0}\quad {\color{#20A900}1}\quad {\color{#624F41}8} Using the basic arithmetic operators ( + , , ÷ , × ) \small(+,-,÷,×) , parentheses and digits above provided(only) on the left side below. Can you make following equation true ? 2 2 2 2 2 2 2 = 2 0 1 8 \large 2\quad 2 \quad 2 \quad 2\quad 2 \quad 2\quad 2= {\color{#D61F06}2}{\color{#3D99F6}0}{\color{#20A900}1}{\color{#624F41}8}

Note :

You can raise the digits in the power (except 0 0 + 0 0^{0+0} )and at least two digits must be used in power with some operators. For example : 8 0 + 1 8^{0+1} or 1 8 + 2 1^{8+2} .

No Yes

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1 solution

Naren Bhandari
Mar 2, 2018

The solution that i come to find is 2 8 + 2 + 2 8 + 1 + 2 8 + 0 + 2 8 1 + 2 8 2 + 2 8 ( 2 + 1 ) + 2 0 + 1 = 2018 2 10 + 2 9 + 2 8 + 2 7 + 2 6 + 2 5 + 2 = 2018 \begin{aligned} &2^{8+2} + 2^{8+1} + 2^{8+0} + 2^{8-1} + 2^{8-2} + 2^{8-(2+1)}+ 2^{0+1} =2018\\& 2^{10} + 2^9 + 2^8 + 2^7 + 2^6 +2^5 +2 =2018\end{aligned} .

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