In the present day scenario, hacking isn't anymore a crime instead it's a survival trait. But when it comes on your part to unlock your own phone and to have forgotten the password, you yourself need to think like a professional hacker.
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The problem gives two main points - Every code has at least 2 digits right - And those 2 digits are wrongly placed
If we first consider 3 and 5 for they appear the most no. of times as the 2 correct digits , then in the last 4 codes they occupy all places that means even if they are correct they occupy all wrong places as per rules given. So, 3 and 5 can't be the two correct digits. From this deduction we get that excluding 3 and 5 , in every code , the other two digits are correct. So , we get , 1, 7, 8 and 2 also 6 and 0 but 6 and 0 don't fulfil the given conditions thus is deduced. Leaving at last with 1, 7, 8 and 2 we see that 2 occupies 1st , 2nd and 3rd place thus it gets the 4th place. 1 occupies 1st , 2nd and 4th place do it gets the 3rd place. 8 occupies 2nd , 3rd and 4th place so it gets the 1st place leaving at last the 2nd place for 7.
*Thus , the password is 8712. Congratulations Hacker ! *