Forming a committee

There are $^{5+3}C_4=70$ ways of making a committee of 4. Out of these, $^5C_4=5$ are comprised of all men. Hence there $70-5=65$ ways of forming a committee with at least 1 woman.

Committee should contain at least one women. ie, more than one woman is possible in a committee.......................................................................................................................................................... No. of ways of choosing a committee including only one woman =3C1x5C3=30................................................................................................................................................. No. of ways of choosing a committee which includes 2 women =3C2x5C2=30................................................................................................................................................. No. of ways of choosing a committee which includes 3 women =3C3x5C1=5.................................................................................................................................................... therefore total ways of selection=30+30+5=65
This is only an alternative way. Better choose easy methods!