A car is travelling at a uniform speed.
The driver sees a milestone showing a -digit number. After travelling for an hour the driver sees another milestone with the same digits in reverse order. After another hour the driver sees another milestone containing the same two digits as in the first one but the two digits separated by a zero ( ).
What is the speed of the car?
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Let the two digit number be represented by 1 0 x + y .
After one hour, the milestone shows the number 1 0 y + x .
The distance traveled so far is: ( 1 0 y + x ) − ( 1 0 x + y ) = 9 ( y − x )
After another hour, the milestone shows 1 0 0 x + y .
The distance traveled in the second hour is: ( 1 0 0 x + y ) − ( 1 0 y + x ) = 9 ( 1 1 x − y ) .
Since the speed is uniform, we have: 9 ( 1 1 x − y ) = 9 ( y − x )
This gives y = 6 x . Since x and y are both digits, x must be 1 and y must be 6 .
Therefore, the milestones mentioned read: 1 6 , 6 1 and 1 0 6 .
Now, since the car traveled 4 5 miles each hour, it is clear that the speed of the car is 4 5 mph.