Four, Can't You Give Me a Better Number?

Find the maximal integer x x such that 4 10000 + 4 27 + 4 x 4^{10000} +4^{27}+4^{x} is a perfect square.


The answer is 19972.

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2 solutions

Vishal Oraon
Sep 13, 2014

A perfect square trinomial is one that has a squared first term, a squared last term, and the middle term is twice the product of first term and last term: a^2 + 2ab + b^2.=(a+b)^2 So, the problem is to find a and b so as to maximize x. a=2^x, b=2^27 (or a=2^27 & b=2^x) This gives x=19972

Why that didn't strike my mind?

We have learnt this in grade 9, still never thought of its converse application.

Ninad Akolekar - 6 years, 6 months ago

Yeah i did same

Aditya Kumar - 5 years, 1 month ago
Tom Engelsman
Dec 15, 2020

Let us rewrite this expression as:

4 10000 + 4 27 + 4 x = 2 20000 + ( 2 27 ) 2 + ( 2 x ) 2 = ( 2 x + 2 27 ) 2 4^{10000} + 4^{27} + 4^{x} = 2^{20000} + (2^{27})^{2} + (2^x)^{2} = (2^x + 2^{27})^2

which requires the term 2 20000 = 2 2 19999 = 2 ( 2 x ) ( 2 27 ) 19999 = x + 27 x = 19972 . 2^{20000} = 2 \cdot 2^{19999} = 2 \cdot (2^x)(2^{27}) \Rightarrow 19999 = x+27 \Rightarrow \boxed{x = 19972}.

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