Find the maximal integer x such that 4 1 0 0 0 0 + 4 2 7 + 4 x is a perfect square.
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Why that didn't strike my mind?
We have learnt this in grade 9, still never thought of its converse application.
Yeah i did same
Let us rewrite this expression as:
4 1 0 0 0 0 + 4 2 7 + 4 x = 2 2 0 0 0 0 + ( 2 2 7 ) 2 + ( 2 x ) 2 = ( 2 x + 2 2 7 ) 2
which requires the term 2 2 0 0 0 0 = 2 ⋅ 2 1 9 9 9 9 = 2 ⋅ ( 2 x ) ( 2 2 7 ) ⇒ 1 9 9 9 9 = x + 2 7 ⇒ x = 1 9 9 7 2 .
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A perfect square trinomial is one that has a squared first term, a squared last term, and the middle term is twice the product of first term and last term: a^2 + 2ab + b^2.=(a+b)^2 So, the problem is to find a and b so as to maximize x. a=2^x, b=2^27 (or a=2^27 & b=2^x) This gives x=19972