Four numbers

Four positive integers ( a , b , c , d a, b, c, d ) satisfy the following: a b = c d ab=cd Is it possible, that if k k is a positive integer, then a k + b k + c k + d k a^k+b^k+c^k+d^k is a prime number?

Yes, it's possible. No, it's not possible.

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1 solution

Áron Bán-Szabó
Aug 30, 2017

Not possible.

a k + b k + c k + d k = a k + b k + c k + a k + b k c k = ( a k + c k ) ( b k + c k ) c k a^k+b^k+c^k+d^k=a^k+b^k+c^k+\dfrac{a^k+b^k}{c^k}=\dfrac{(a^k+c^k)(b^k+c^k)}{c^k} Since a k + c k > c k a^k+c^k>c^k and b k + c k > c k b^k+c^k>c^k so after the simplification, the two-factor product's factors are bigger, than 1, so it is a composite number.

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