Four prime factors

We know that $27000001 = 27 \times 1000000 + 1$ $= 3^{3} \times 100^{3} + 1$ $= (3 \times 100 + 1)(3^{2} \times 100^{2} - 3 \times 100 + 1)$ $= 301 ((3 \times 100 + 1)^{2} - 9 \times 100)$ $= 7 \times 43 (3 \times 100 - 3 \times 10 + 1)(3 \times 100 + 3 \times 10 +1)$ $= 7 \times 43 \times 271 \times 331$ So, 7, 43, 271, and 331 are prime factors of 27000001. So, their sum is $7+43+271+331 = \boxed{652}$ .