( x + 5 ) 2 + ( y + 2 ) 2 = 1 6 and ( x − 3 ) 2 + ( y − 4 ) 2 = 2 5 , there are four tangents to them, at the same time.
Given two circles with equationsIf two of them are: y = d a ± b c x + d e ± f c And the other two are: y = k g ± h j x + k l ± m j
Find a + b + c + d + e + f + g + h + j + k + l + m , where the equations of the line are in its simplest form.
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