Only 1-9 distinct digits are allowed to use in every four cases. Can we make all four equations true?
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2 + 7 + 3 = 1 2 ⟶ Abundant number
1 0 − 1 − 4 = 5 ⟶ Rational number
2 × 4 × 1 = 8 ⟶ Fibonacci number
Now considering the last equation.
◯ ÷ ◯ ÷ ◯ = Perfect number
Between 1 and 9, 6 is the only perfect number. It is impossible to get 6 in this case.
Hence the answer is no