Four type of numbers

+ + = Abundant number \bigcirc + \bigcirc + \bigcirc = \text{Abundant number}

= Rational number \bigcirc - \bigcirc - \bigcirc = \text{Rational number}

× × = Fibonacci number \bigcirc \times \bigcirc \times \bigcirc = \text{Fibonacci number}

÷ ÷ = Perfect number \bigcirc \div \bigcirc \div \bigcirc = \text{Perfect number}

Only 1-9 distinct digits are allowed to use in every four cases. Can we make all four equations true?

No Yes

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1 solution

Munem Shahriar
Oct 17, 2017

2 + 7 + 3 = 12 Abundant number 2 + 7 + 3 = 12 \longrightarrow \text{Abundant number}

10 1 4 = 5 Rational number 10- 1 -4 = 5 \longrightarrow \text{Rational number }

2 × 4 × 1 = 8 Fibonacci number 2 \times 4 \times 1 =8 \longrightarrow \text{Fibonacci number}

Now considering the last equation.

÷ ÷ = Perfect number \bigcirc \div \bigcirc \div \bigcirc = \text{Perfect number}

Between 1 and 9, 6 is the only perfect number. It is impossible to get 6 in this case.

Hence the answer is no \color{#20A900} \boxed{\text{no}}

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