Four

$The~sum~that~we~need~to~count~is:$ $S=\displaystyle \sum_{n=1}^{25} 4n=4+8+\cdot\cdot\cdot+100$ $The~sum~is~given~by:$ $\frac{(first~number+last~number) \times amount~of~numbers}{2}$ $And~the~amount~of~numbers \in S~is:$ $\frac{100-4}{4}+1=\frac{96}{4}+1=24+1=25$ $So:$ $S=\frac{(100+4) \times 25}{2}=\frac{2 \times (50+2) \times 25}{2}=(50+2) \times 25=52 \times 25=1300$ $Hence,~the~answer~is:$ $\huge \color{#EC7300}{\boxed{\color{#D61F06}{1300}}}$