Fractal from Sqrt!

Algebra Level 3

a + b c + d a + b c + d a + b ⋱ = 6 \Large a + \dfrac b{c + \dfrac d{a + \dfrac b{c+\dfrac d{a + \dfrac b{\ddots}}}}} = \sqrt 6

The equation above holds true for some positive integers a a , b = 1 b=1 , c c , and d d . Find a + b + c + d a + b + c + d .


The answer is 13.

Pepper Mint by Pepper Mint , 20, South Korea

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Pepper Mint
Sep 2, 2017

1 Helpful 0 Interesting 1 Brilliant 0 Confused

Note: This approach doesn't explain why a , b , c , d a, b, c, d are uniquely determined.

Calvin Lin Staff - 3 years, 9 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...