Fraction!

Here, xy=2(x+y)

Now sum of the reciprocals of x and y is,

1/x+1/y = (x+y)/(xy) = (x+y)/(2(x+y)) = 1/2

Let the two numbers be $x$ and $y$ . Then the first equation is

$xy=2(x+y)$

The sum of their reciprocals is

$\dfrac{1}{x}+ \dfrac{1}{y}$

The sum of their reciprocals can also be written as

$\dfrac{1}{x}+ \dfrac{1}{y}=\dfrac{y+x}{xy}$

Substitute the first equation to the above equation, we have

$\dfrac{y+x}{xy}=\dfrac{y+x}{2(y+x)}=\boxed{\dfrac{1}{2}}$