Fraction

From the equation above, we will get $8y < 30x < 9y$ . As we need to keep the lowest $y$ , we need to set the lowest $x$ as well. Setting $x = 1$ gives $8y < 30 < 9y$ or $\frac{10}{3} < y < \frac{15}{4}$ , which lies between 3.333... and 3.75. No integer $y$ would be in between this range.

By setting $x = 2$ we will get $8y < 60 < 9y$ , or put it simply $\frac{20}{3} < y < \frac{15}{2}$ This lies between 6.666 and 7.5, so the least positive integer $y$ satisfying this inequality will be $y = 7$

its 2/7 =0.28571

which lies between 0.2666666 and .30