Fraction between fractions

Find the smallest value of the positive integer n n such that:

For each positive integer m < 2017 m<2017 there exists some integer k k such that

m 2017 < k n < m + 1 2018 \frac { m }{ 2017 } <\frac { k }{ n } <\frac { m+1 }{ 2018 }


The answer is 4035.

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1 solution

Keanu Ac
Jun 9, 2017

To find the smallest denominator that will be between 2017 and 2018 is 4035. This works because the minimum distance between any two integers is 1, multiplying both by 2 leaves one integer in between them.

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