2 0 1 4 1 + 2 0 1 4 3 + 2 0 1 4 5 + ⋯ + 2 0 1 4 2 0 1 3 = ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The numerators are the first 1007 odd numbers so that their sum is 1 0 0 7 2 . The total comes out to be 2 0 1 4 1 0 0 7 2 = 4 2 0 1 4 = 5 0 3 . 5
The sum is equivalent to 2 0 1 4 1 ( n = 1 ∑ 1 0 0 7 ( 2 n − 1 ) ) . Which when simplified comes out to 2 0 1 4 ( 1 0 0 7 ) 2 = 5 0 3 . 5 .
Problem Loading...
Note Loading...
Set Loading...
1+2013=2014
3+2011=2014
5+2009=2014
.........
2013+1=2014
There are 2 1 + 2 0 1 3 =1007 pairs of numbers that add up to 2014.
So 1+3+5+...+2013= 2 1 0 0 7 × 2 0 1 4 =1007 × 1007
2 0 1 4 1 0 0 7 × 1 0 0 7
= 2 1 0 0 7
=503.5