1 2 3 4 5 6 7 9 0 2 + 1 2 3 4 5 6 7 8 8 2 − 1 2 3 4 5 6 7 8 9 2 − 2 1 2 3 4 5 6 7 8 9 2
Calculate the value of the expression above.
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Let 123456789=a, then the expression can be written as a^2/[(a+1)^2 +(a-1)^2 - 2]
Now the denominator is 2(a^2+1^2) - 2= 2a^2
so the answer is 1/2 and not 1 as given.
I too got the same result.
Let 123456789=a, then the expression can be written as a^2/[(a+1)^2 +(a-1)^2 - a^2-2] Therefore denominator is a^2 and answer is 1
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Thanks. The problem phrasing was changed so that the answer is now 1. I have updated the answer accordingly.
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ummm why do i still end up with 1?
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let a=123456789
rewriting:
(a^2) / [(a+1)^2+(a-1)^2-a^2-2]
Expanding the binomials
(a^2)/[a^2+2a+1+a^2-2a+1-a^2-2]
Now, simplifying
(a^2)/(a^2)
Then simplifying again, we get 1, so the answer is "1"