Free energy change and electrical work done in a cell

The e.m.f of the cell reaction, $\ce{Zn}(\text s) + \ce{Cu^2+} (\text{aq}) \ce{->} \ce{Zn^2+} (\text{aq}) + \ce{Cu}(\text s)$ is $1.1\text{ V}$ . Calculate free energy change for the reaction if enthalpy of the reaction is $-216.7~ \text {KJ mol}^{-1}$ ,calculate the entropy change for the reaction(in $\text {J}\text {K}^{-1}\text {mol}^{-1}$ .