Free Fall
As shown above, a black bowling ball is dropped from a hot-air balloon which is ascending straight upwards at a constant speed of
m/s. The height of the bowling ball at the moment of the drop is
and its highest height before it fell on the ground
seconds after the drop is
What is the ratio
?
Gravitational acceleration is and air resistance is negligible.
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Initial velocity of ball is v=10 m/s.So the distance H-h=v.v/2.g=5 m..........(1)
and time taken will be 5=g.t.t/2,that is t=1 sec. .
So the time taken by ball to travel distance H is (3-1=)2 sec by initial velocity=0 m/s so H=0+(g.2.2)/2=20 m...................(2)
Using H=20 m into (1) we get h=15 m
So h/H=15/20=3/4.