Free the fly

Geometry Level pending

A fly is trapped inside a hollow cube. It moves from A A to B B along the edges of the cube, taking the shortest possible route. It then comes back to A A , again along the edges, taking the longest route (without going over any point more than once). If the total distance travelled is 504 504 cm, what is the area of a face of the cube (in c m 2 cm^2 )?

5184 7056 6241 3969

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Marta Reece
Jun 11, 2017

It takes 2 2 edges for the shortest distance (blue) and 6 6 for the longest (green).

(There are several ways the longest distance can be accomplished. Only one of them is pictured on the left.)

The total trip comes to 8 8 edges.

The length of an edge is therefore 504 8 = 63 \dfrac{504}{8}=63 cm.

Area of a face is 6 3 2 = 3969 63^2=\boxed{3969} cm 2 ^2

Nice! With enough trial and error, we can see that the shortest route will take 2 2 edges and the longest route 6 6 edges. Is there perhaps a more rigorous way to prove these?

Zach Abueg - 3 years, 12 months ago

Log in to reply

I have actually gone through all the possible paths to make sure I was right, but it's tedious and difficult to communicate. It is not hugely difficult though, as symmetry helps and many of the paths are obvious dead ends.

Marta Reece - 3 years, 12 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...