Suppose the charge( +q ) and the hollow conducting sphere( charged to +q/2 ) are kept , as shown in the figure , for a while. Now, suddenly using a freeze gun we convert the conducting material of the sphere into a non-conducting material , so that the charge distribution on the sphere gets frozen like that !
Now, suppose , the +q charge is replaced by a -q/2 charge at the same position(at which the original +q charge was present).
Find the Dipole moment of the charge system.
This problem is Original
Note : q = 4/R (Numerically) and d = 2R Where R is the radius of the hollow sphere.
Hint : You don't need to know from where the freeze gun did come from :)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
This problem requires the knowledge of image charges .