Freeze the charges!

Suppose the charge( +q ) and the hollow conducting sphere( charged to +q/2 ) are kept , as shown in the figure , for a while. Now, suddenly using a freeze gun we convert the conducting material of the sphere into a non-conducting material , so that the charge distribution on the sphere gets frozen like that !

Now, suppose , the +q charge is replaced by a -q/2 charge at the same position(at which the original +q charge was present).

Find the Dipole moment of the charge system.

This problem is Original

Note : q = 4/R (Numerically) and d = 2R Where R is the radius of the hollow sphere.

Hint : You don't need to know from where the freeze gun did come from :)


The answer is 5.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Richeek Das
Dec 2, 2018

This problem requires the knowledge of image charges .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...