Friction on a ski slope

A ski slope with kinetic friction coefficient 0.21 is 200 m long in the horizontal direction. If a person were to ski on this slope and stopped 100 m (in the horizontal direction) from the starting point, find the difference in height between those points!

Assumption : The ski slope can take any shape such that every point in the ski slope is lower than the starting point

790 210 1580 420

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1 solution

If we take a section of the slope with length d l \mathrm{d}l and angle of inclination θ \theta , we will find that the kinetic frictional force acting on an object with mass m m on that slope section is : f = μ m g cos θ f = \mu mg \cos \theta .

And since the height difference is caused by potential energy that is diminished by the frictional work, we can use the work - energy theorem :

0 L f d l = m g Δ h \int_0^L f \,\mathrm{d}l = mg \Delta h

μ m g 0 L cos θ d l = m g Δ h \mu mg \int_0^L \cos \theta\, \mathrm{d}l = mg \Delta h

μ 0 s d x = Δ h \mu \int_0^s \mathrm{d}x = \Delta h

Δ h = μ s = 210 m \Delta h = \mu s = 210 m

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