Friendly Quadritics

Algebra Level 4

Quadratic (A) is a friend of quadratic (B) if both the roots of (A) lie between the roots of (B).

Then find the number of integral values of a a for which x 2 100 x + a 2 = 0 x^{2}-100x+a^{2}=0 is a friend of x 2 100 x + 2 a 2 14 a + 33 = 0 x^{2}-100x+2a^{2}-14a+33=0 .


The answer is 7.

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2 solutions

Tay Yong Qiang
Aug 18, 2015

Notice that by translating f ( x ) f(x) upwards, we obtain g ( x ) g(x) which will have roots between that of f ( x ) f(x) , hence a friend of f ( x ) f(x) , similar to what the picture has shown.

We therefore need a 2 14 a + 33 < 0 a^2-14a+33<0

( a 3 ) ( a 11 ) < 0 (a-3)(a-11)<0

Since a a takes on integral values, a = 4 , 5 , 6 , 7 , 8 , 9 a=4,5,6,7,8,9 or 10 10 , which gives us 7 \boxed{7} solutions.

Can u please recheck ur soln.

Mehul Chaturvedi - 5 years, 3 months ago

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Yes you are right as close the roots get the more is their product so Product of roots of A is greater than Product of roots of B.

Kushagra Sahni - 5 years, 2 months ago
Mehul Chaturvedi
Mar 9, 2016

To be a friend, the graph of A A has to lie completely above \color{#D61F06}{\text{above}} B B i.e A > B \color{#3D99F6}{\underline{A > B}}

x 2 100 x + a 2 > x 2 100 x + 2 a 2 14 a + 33 a 2 14 a + 33 < 0 ( a 11 ) ( a 3 ) < 0 a ( ( 3 , 11 ) a 4,5,6,7,8,9,10 x^{2}-100x+a^{2} > x^{2}-100x+2a^{2}-14a+33 \\ a^2-14a+33 < 0 \\ (a-11)(a-3)<0 \\ \therefore a \in {\color{#3D99F6}{\boxed{\color{#D61F06}{\boxed{(\color{#69047E}{(3,11)}}}}}} \\ \therefore a\in \text{{4,5,6,7,8,9,10}}

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