There are x cows, y bulls, z hens, in a Farm. One stockman* can take care of 15 animals. It is stated that z = 4 5 .
The number of cows is half the number of bulls.
If total number of heads in the farm is less-than total number of legs (or feet) by 186 (including the stockman), the total number of stockman in the farm is?
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Let the number of stockman be w
It is given that x = 2 1 y ⟹ y = 2 x ⟹ Eq.(1)
We know that each stockman takes care of 1 5 animals. Therefore,
1 5 x + y + z = w
Substitute z = 4 5 and Eq.(1):
x + 2 x + 4 5 = 1 5 w 3 x = 1 5 w − 4 5
x = 5 w − 1 5 ⟹ Eq.(2)
Given that:
Total legs − Total heads = 1 8 6
( 2 w + 4 x + 4 y + 2 z ) − ( w + x + y + z ) = 1 8 6 w + 3 x + 3 y + z = 1 8 6
Substitute z = 4 5 , Eq.(1) and Eq.(2):
w + 3 ( 5 w − 1 5 ) + 3 ( 2 x ) + 4 5 = 1 8 6 w + 1 5 w − 4 5 + 6 ( 5 w − 1 5 ) + 4 5 = 1 8 6 1 6 w + 3 0 w − 9 0 = 1 8 6 4 6 w = 2 7 6 w = 6
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Cows = x , Bulls = y , Hens = z = 45, Caretakers or stockman c
x = 2 1 y => y = 2 x
1 caretaker can take care of 15 animals, ie
1 caretaker = 15 animals
1 5 1 caretakers = 1 animal
Therefore, total no of animals ( x + y + 4 5 ) = 1 5 1 ( x + y + 4 5 ) caretakers
= 1 5 1 ( x + 2 x + 4 5 ) caretakers = 1 5 1 ( 3 x + 4 5 ) caretakers = 1 5 3 ( x + 1 5 ) caretakers = 5 1 ( x + 1 5 ) caretakers
So, total no of caretakers = 5 1 ( x + 1 5 ) ---- 1
Total no of heads is less than total no of legs by 186
ie, Total no of legs - Total no of heads = 186
Total no of heads = total no of animals + total no of caretakers ( no human or animals have 2 or more heads O-o) = ( 3 x + 4 5 ) + ( 5 1 ( x + 1 5 )) = ( 5 1 ( 1 6 x + 2 4 0 ))
Total no of feet/legs = 4 ( cows + bulls) + 2 ( hen + caretakers) = ( 4 × 3 x ) + 2 ( 4 5 + 5 1 ( x + 1 5 )) = 1 2 x + 2 ( 5 2 4 0 + x ) = 5 6 2 x + 4 8 0
Therefore, ( 5 6 2 x + 4 8 0 ) - (( 5 1 ( 1 6 x + 2 4 0 ))) = 186
=> 5 4 6 x + 2 4 0 = 186
=> 4 6 x + 2 4 0 = 930
=> 4 6 x = 690
=> x = 15
Total no of cows = 15.
Total no of caretakers = 5 1 ( x + 1 5 ) 1
=> Caretakers = 5 1 ( 1 5 + 1 5 ) = 6
Therefore, Total no of caretakers = 6 !!