From this moment, I hate animals! `Farmer's Brain`

Algebra Level pending

There are x {x} cows, y {y} bulls, z {z} hens, in a Farm. One stockman* can take care of 15 animals. It is stated that z = 45 {z} = 45 .

The number of cows is half the number of bulls.

If total number of heads in the farm is less-than total number of legs (or feet) by 186 (including the stockman), the total number of stockman in the farm is?


The answer is 6.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Viki Zeta
May 26, 2016

Cows = x {x} , Bulls = y {y} , Hens = z {z} = 45, Caretakers or stockman c {c}

x = {x}= 1 2 \frac{1}{2} y {y} => y = 2 x {y}= 2{x}

1 caretaker can take care of 15 animals, ie

1 caretaker = 15 animals

1 15 \frac{1}{15} caretakers = 1 animal

Therefore, total no of animals ( x {x} + y {y} + 45 {45} ) = 1 15 \frac{1}{15} ( x {x} + y {y} + 45 {45} ) caretakers

= 1 15 \frac{1}{15} ( x {x} + 2 x {2x} + 45 {45} ) caretakers = 1 15 \frac{1}{15} ( 3 x {3x} + 45 {45} ) caretakers = 3 15 \frac{3}{15} ( x {x} + 15 {15} ) caretakers = 1 5 \frac{1}{5} ( x {x} + 15 {15} ) caretakers

So, total no of caretakers = 1 5 \frac{1}{5} ( x {x} + 15 {15} ) ---- 1 \boxed{1}

Total no of heads is less than total no of legs by 186

ie, Total no of legs - Total no of heads = 186

Total no of heads = total no of animals + total no of caretakers ( no human or animals have 2 or more heads O-o) = ( 3 x {3x} + 45 {45} ) + ( 1 5 \frac{1}{5} ( x {x} + 15 {15} )) = ( 1 5 \frac{1}{5} ( 16 x {16x} + 240 {240} ))

Total no of feet/legs = 4 ( cows + bulls) + 2 ( hen + caretakers) = ( 4 × 3 x 4 \times {3x} ) + 2 2 ( 45 45 + 1 5 \frac{1}{5} ( x {x} + 15 {15} )) = 12 x 12{x} + 2 ( 240 + x 5 ) 2(\frac{240 + {x}}{5}) = 62 x + 480 5 \frac{62{x} + 480}{5}

Therefore, ( 62 x + 480 5 \frac{62{x} + 480}{5} ) - (( 1 5 \frac{1}{5} ( 16 x {16x} + 240 {240} ))) = 186

=> 46 x + 240 5 \frac{46{x} + 240}{5} = 186

=> 46 x + 240 46{x} + 240 = 930

=> 46 x 46{x} = 690

=> x {x} = 15

Total no of cows = 15.

Total no of caretakers = 1 5 \frac{1}{5} ( x {x} + 15 {15} ) 1 \boxed{1}

=> Caretakers = 1 5 \frac{1}{5} ( 15 {15} + 15 {15} ) = 6

Therefore, Total no of caretakers = 6 !!

Hung Woei Neoh
May 30, 2016

Let the number of stockman be w w

It is given that x = 1 2 y y = 2 x x=\dfrac{1}{2}y \implies y=2x\implies Eq.(1)

We know that each stockman takes care of 15 15 animals. Therefore,

x + y + z 15 = w \dfrac{x+y+z}{15}=w

Substitute z = 45 z=45 and Eq.(1):

x + 2 x + 45 = 15 w 3 x = 15 w 45 x+2x+45=15w\\ 3x=15w-45

x = 5 w 15 x=5w-15 \implies Eq.(2)

Given that:

Total legs - Total heads = 186 =186

( 2 w + 4 x + 4 y + 2 z ) ( w + x + y + z ) = 186 w + 3 x + 3 y + z = 186 (2w+4x+4y+2z) - (w+x+y+z) = 186\\ w+3x+3y+z=186

Substitute z = 45 z=45 , Eq.(1) and Eq.(2):

w + 3 ( 5 w 15 ) + 3 ( 2 x ) + 45 = 186 w + 15 w 45 + 6 ( 5 w 15 ) + 45 = 186 16 w + 30 w 90 = 186 46 w = 276 w = 6 w+3(5w-15)+3(2x)+45=186\\ w+15w-45+6(5w-15)+45=186\\ 16w+30w-90=186\\ 46w=276\\ w=\boxed{6}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...