Taxi!

{ a 3 = b 3 + c 3 d 3 a = b + c 7 d \begin{cases}{a^3=b^3+c^3-d^3} \\ {a \ \ =b+c-7d}\end{cases}

Positive integers a , b , c , d a,b,c,d satisfy the above system of equations. Find the value of a + b + c + d a+b+c+d .

32 -32 23 -23 32 32 23 23

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2 solutions

Shivamani Patil
Oct 27, 2014

Logical answer :

as a = b + c 7 d a=b+c-7d

we get a + b + c + d = b + c 7 d + b + c + d = 2 b + 2 c 6 d = 2 ( b + c 3 c ) a+b+c+d=b+c-7d+b+c+d=2b+2c-6d=2(b+c-3c)

As all are positive integers and notice a + b + c + d a+b+c+d has 2 2 as factor.

So we have answer as 32 32

Manuel Kahayon
Jan 23, 2016

The title of the problem is actually referring to taxicab numbers which can be expressed as the sum of two distinct pairs of cubes.

The most famous of these numbers is 1729 1729 , which can be expressed as either 1 0 3 + 9 3 10^3 +9^3 or 1 2 3 + 1 3 12^3+1^3 .

So, we get 10 + 12 + 9 + 1 = 32 10+12+9+1 = 32 .

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