Fruit in a bag

Probability Level 1

Say you have 6 apples and 7 oranges. You put them in a bag, and pull one out. The odds of taking an apple is 6/13. Now imagine that you randomly take one fruit out of the bag, but you don't look at it. You then take out a second piece of fruit. What are the chance that the second fruit is an orange?

7/13 6/12 6/13 7/12

Hillel Ringelblum by Hillel Ringelblum , 15, Australia

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1 solution

The required probability is 6 13 × 7 13 + 7 13 × 7 13 = 7 13 \dfrac{6}{13}\times \dfrac{7}{13}+\dfrac{7}{13}\times \dfrac{7}{13}=\dfrac{7}{13}

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I understood the question differently (without putting the first fruit back) but still got to the same answer.

6 13 ⋅ 7 12 + 7 13 ⋅ 6 12 = 7 13 \frac{6}{13} \cdot \frac{7}{12} + \frac{7}{13} \cdot \frac{6}{12} = \frac {7}{13} .

Henry U - 1 year, 6 months ago

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