Fruits and boxes
There are 4 fruits, apples, oranges, pears and peaches. There are three boxes A B and C. (don't think of pigeonhole principle) All of the fruits of a type go exactly in one box. And no box can have fruits of more than one type. But Apples cannot go in box A, Either Oranges or Pears have to go in box B. In how many ways can this be done ?
PS: It's okay if one of the fruits gets left out.
The answer is 8.
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1 solution
this problem can be solved using possibility trees since the numbers are small. Also here's a proper solution
for step 1 this can be done in 2C1 ways ( either oranges or pears) for step 2 this can be done in 2C1 ways (not selected in step 1 , apples not allowed, and peaches ) for step 3 this can be done in 2C1 ways (not selected in step 2 and apples)
2C1x2C1x2C1 = 2x2x2 = 8