∫ 0 1 exp ( x + e x + e e x + e e e x ) d x
If the above integral can be expressed as
A e − B e
for positive integers A and B , find A + B .
Notations :
exp ( x ) denotes the exponential function, exp ( x ) = e x .
n a denotes the Tetration function, n a = n number of a ’s a a a ⋅ ⋅ a .
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You got the key to solve this problem. well done!
PS it should be 7 as the answer not 9
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f ( n ) = ∫ 0 1 e x e e x . . . . n times e e e . . . d x make the y-sub y = e x and changing y to x: f ( n ) = ∫ 1 e e x e e x . . . . n-1 times e e e . . . d x then by induction we would have f ( n ) = ∫ n − 1 e n e d x = n e − n − 1 e Put n =4 and get the answer.