Suppose the decimal expansion of a certain fraction b a takes the form
0 . 0 1 0 2 0 3 0 4 0 5 . . . 9 7 9 9 0 0
wherein the series of digits skip 98, and then recurrs. If a and b are coprime positive integers, determine a + b .
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Yes, the reports in the problem specifically pointed out the omission of the term 98 in the decimal expansion.
Let f ( x ) = 1 + 2 x + 3 x 2 + ⋯ , then 1 0 − 2 f ( 1 0 − 2 ) = 0 . 0 1 0 2 0 3 0 4 0 5 . . . 9 7 9 9 0 0
9 8 is skiped since the 1 0 0 t h term carries 1
∫ 0 x f ( t ) d t = x + x 2 + x 3 + ⋯ = 1 − x x
f ( x ) = d x d 1 − x x = ( 1 − x ) 2 1
1 0 − 2 f ( 1 0 − 2 ) = 9 8 0 1 1 0 0
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Let the answer be S
S = 1 0 2 1 + 1 0 4 2 + 1 0 6 3 + 1 0 8 4 + . . .
1 0 0 1 S = 1 0 4 1 + 1 0 6 2 + 1 0 8 3 + . . .
Subtracting, we get
1 0 0 9 9 S = 9 9 1
S = 9 8 0 1 1 0 0
There is a little wrong , the center part should be . . . 9 7 9 9 0 0 0 1 0 2 0 2 . . .