Solve your way through the following steps and submit the result of (c) as your answer.
(a) First, prove that for all values of
The logical reasoning behind this proof will help in parts (b) and (c).
(b) Sketch, on the same axes, the curves representing and
(c) Express in the form and hence, without integrating or making use of any approximations, state the area enclosed between the two curves and the coordinate axes.
Note: This problem can easily be worked out with a calculator, online maths website or by integrating directly. But that will take all the fun out of it! The question is based on the typical calculus A-level syllabus. Please follow the rules and arrive to the answer by following all the below steps chronologically.
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I ( n ) = = = ∫ 0 1 ( x n ( n + 1 ) 2 − 1 ) d x n + 1 1 ( n + 1 ) 2 − 1 n Now we want to use this information to evaluate ∫ 0 1 ( 1 6 x 3 − 1 ) d x . First notice that 1 6 = ( 3 + 1 ) 2 so what we have is ∫ 0 1 ( x 3 ( 3 + 1 ) 2 − 1 ) d x , meaning n = 3 ∴ I(3) = 3 .