Given the points P ( 0 , − 2 ) and Q ( − 7 , 4 ) , find the equation of the moving point A such that ∠ P A Q is always 9 0 ° .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Easiest solution there is, Steven!
The locus is a circle with diameter P Q - this is an application of Thales's theorem (or in fact of its converse).
The centre of the circle is the midpoint of P Q (ie ( − 2 7 , 1 ) ); the radius is half the distance P Q (ie 2 8 5 ). Its equation is then
( x + 2 7 ) 2 + ( y − 1 ) 2 = 4 8 5
which after simplifying becomes
x 2 + y 2 + 7 x − 2 y − 8 = 0
Problem Loading...
Note Loading...
Set Loading...
The dot product between a vector from ( x , y ) to ( P x , P y ) and a vector from ( x , y ) to ( Q x , Q y ) should be zero :
( Q x − x ) ( P x − x ) + ( Q y − y ) ( P y − y ) = 0 ( − 7 − x ) ( 0 − x ) + ( 4 − y ) ( − 2 − y ) = 0 x 2 + y 2 + 7 x − 2 y − 8 = 0