P ( x ) is a monic polynomial.
And
y = P ( x ) and
y = 2 x + 1 . Meet at
x = 1 , 2 , 3 , 4
Find P ( 0 )
Given that P ( x ) is a polynomial of degree 4
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Consider g ( x ) = P ( x ) − ( 2 x + 1 ) .
Clearly, g ( x ) is monic polynomial of degree 4 and it has roots x = 1 , 2 , 3 , 4 .
g ( x ) = ( x − 1 ) ( x − 2 ) ( x − 3 ) ( x − 4 ) ⇒ P ( x ) = ( x − 1 ) ( x − 2 ) ( x − 3 ) ( x − 4 ) + ( 2 x + 1 ) P ( 0 ) = 4 ! + 1 = 2 5
@Parth Lohomi This is overrated!!
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