Fun with optics!
Water (with refractive index ) in a tank is 18 cm. Oil of refractive index lies on water making a convex surface of radius of curvature . Consider oil to act as a thin lens. An object is placed above water surface. The location of its image is at above the bottom of the tank. What is the value of ?
The answer is 2.
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1 solution
first we need find the focus of the lens, by lensmaker formula we get it to be 9.6 cm. now we will use 1/v+1/u = 1/f. u= -24 cm and f= 9.6 cm, we get v= 16 cm. in the question it is asked to find the distance from the bottom, which is 18-16= 2 cm