Let there be a function such that
If , where represents the Lambert's W function determine , where is the Omega constant .
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First we take that the solution to such functional differential equation is of the form
f ( x ) = c 1 e A x
for some unknown constant A and some arbitrary constant c 1 .
Substituting that to the said differential equation,
c 1 A e A x = c 1 e A ( x − 1 )
c 1 A e A x = c 1 e − A e A x
A = e − A
A e A = 1
A = W ( 1 ) = Ω ≈ 0 . 5 6 7 1 4 3
Where Ω is the Omega Constant . This means our function is
f ( x ) = c 1 e W ( 1 ) x
Now, the Lambert's W function has the property such that
e W ( x ) = W ( x ) 1
So we can rephrase the function as
f ( x ) = c 1 [ W ( 1 ) ] − x
From which we can see that since f ( π ) = [ W ( 1 ) ] − π , so that makes c 1 = 1 .
From here we can now determine f ( Ω 1 ) .
f ( Ω 1 ) = e Ω × Ω 1 = e
And thus, ⌊ 1 0 0 0 × e ⌋ = 2 7 1 8 .