Functional integral
Calculus
Level
4
- f(x) = 1-|x| , 0<|x|<1 , and
- f(x) = 0 , x=0 , and
- f(x) = |x|-1 , |x|>1
- g(x) = f(x-1) + f(x+1).
- find value of definite integral of g(x) when X lies in [-5,3].
The answer is 24.
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1 solution
it is easy to break f(x) in intervals and then express g(x)....then evaluate integral to get the answer