Functional

Algebra Level 2

Let x x be a positive real number.

Let y = f ( x ) = x x y = f(x) = \sqrt{x} - x

Find the maximum value of y y


The answer is 0.25.

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2 solutions

By completing the square, we have that y = ( x x ) = ( x 1 2 ) 2 + 1 4 y = -(x - \sqrt{x}) = -\left(\sqrt{x} - \dfrac{1}{2}\right)^{2} + \dfrac{1}{4} ,

which describes a parabola opening downward with a maximum of 1 4 = 0.25 \dfrac{1}{4} = \boxed{0.25} at x = 1 2 x = 1 4 \sqrt{x} = \dfrac{1}{2} \Longrightarrow x = \dfrac{1}{4} .

Denton Young
May 8, 2017

Taking the derivative, there is a maximum at x = 0.25 x = 0.25

Substituting that value of x x , we get y = 0.5 0.25 = 0.25 y = 0.5- 0.25= 0.25

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