Functions
Algebra
Level
2
A function f exists such that (m + n) divides ( f(m) + f(n) ) for all positive integers m and n. Then the value of f(x) is
Dosen't exist
0
kx , k is any constant
x
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1 solution
Here,[f(m)+f(n)] /(m+n) = k , where k is any constant. Hence by above function, f(x)/x = k. So, f(x) = xk