If f (x) = a+bx and f ( f ( f ( f (x))))= 256x + 425, and if a and b are positive real numbers, then (a-b )=?
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Wrong. The value of b is ± 4 . For b = 4 , we have a = 5 and for b = ( − 4 ) , we have a = 3 − 2 5 . Both are correct and valid answers. You should edit the problem to say that " a and b are positive real numbers" .
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Thanks. I have updated the question accordingly. Great that you noticed that multiple solutions are possible.
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f(x)=a+bx or f(f(x))=a+b(a+bx)=a+ab+b^2x like that f ( f ( f ( f (x))))=a+ab+ab^2+ab^3+b^4x=256x+425 so b^4x=256x or b=4. now a+4a+a(4^2)+a(4^3)=425 or 85a=425 or a=5 So a-b=1