Fundamental property?

Geometry Level 2

We know that sin ⁡ 0 = sin ⁡ π = sin ⁡ 2 π = sin ⁡ 3 π = ⋯ = sin ⁡ ( n π ) \sin 0 = \sin \pi = \sin2\pi = \sin3\pi = \cdots = \sin (n\pi) .

So is it true that the fundamental period of then function f ( x ) = sin ⁡ x f(x) =\sin x is π \pi ?

No, it is not true Yes, it is true

Pi Han Goh by Pi Han Goh , 30, Malaysia

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Shourya Pandey
Feb 16, 2017

We have s i n π 6 = 1 2 sin \frac{\pi}{6} = \frac{1}{2} , but s i n 7 π 6 = − 1 2 sin \frac {7\pi}{6} = \frac{-1}{2} . So π \pi is not the fundamental period of s i n sin . In fact, 2 π 2\pi is its fundamental period.

1 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...