Gambler's Ruin in Tennis?

Alex and Bob are playing a game of tennis. At any given time, the probability of Alex winning a point is 3 5 \dfrac{3}{5} , and thus Bob's chance of winning each point is 2 5 \dfrac{2}{5} . If p p is Alex's probability of winning each Game, find the value of p p to the nearest thousandth.

Note: In a tennis game, a player wins as soon as he/she has scored at least 4 4 points AND at least 2 2 more points than the opponent.. Assume it is possible for the game to continue indefinitely.


The answer is 0.736.

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1 solution

Pop Wong
May 31, 2020

The possible scenario Alex wins the game:

Alex Bob Next Scenario Pr Note
40 0 Alex win next pt Pr = ( 3 / 5 ) 3 ( 2 / 5 ) (3/5)^{3} *(2/5) 2025 15625 \frac{2025}{15625}
40 15 Alex win next pt Pr = 4 C 1 ( 3 / 5 ) 3 ( 2 / 5 ) ( 3 / 5 ) 4C1 (3/5)^3 (2/5) * (3/5) 3240 15625 \frac{3240}{15625}
40 30 Alex win next pt Pr = 5 C 2 ( 3 / 5 ) 3 ( 2 / 5 ) 2 ( 3 / 5 ) 5C2 (3/5)^3 (2/5)^2 * (3/5) 3240 15625 \frac{3240}{15625}
40 40 Alex win the deduce with Pr= P d P_d Pr= 6 C 3 ( 3 / 5 ) 3 ( 2 / 5 ) 3 6C3 (3/5)^3(2/5)^3 * P d P_d 4320 15625 \frac{4320}{15625} * P d P_d

P d P_d = Pr(Alex wins next two pt) + Pr(Re-deduce) * P d P_d

P d P_d = ( 3 / 5 ) ( 3 / 5 ) + 2 ( 3 / 5 ) ( 2 / 5 ) (3/5)(3/5) + 2(3/5)(2/5) * P d P_d

P d P_d = 9 25 \frac{9}{25} * 25 13 \frac{25}{13} = 9 13 \frac{9}{13}

Pr(Alex wins) = Sum all prob. = 0.736

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