Game of function

Algebra Level 2

A non-constant function f(x) is such that f(2x)= [ f ( x ) ] 2 [f(x)]^2 .

Find the value of x if f(x)=1.


This is an original problem and belongs to my set Raju bhai's creations

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2 solutions

Skanda Prasad
Oct 31, 2017

Given f ( 2 x ) = ( f ( x ) ) 2 f(2x)=(f(x))^2

And f ( x ) = 1 f(x)=1

Substituting in the first equation, we get,

f ( 2 x ) = 1 2 f(2x)=1^2

\implies f ( 2 x ) = 1 f(2x)=1

\implies f ( 2 x ) = f ( x ) f(2x)=f(x)

\implies x = 2 x x=2x

\implies x ( 2 1 ) = 0 x(2-1)=0

\implies x = 0 \boxed{x=0}

Rajath Rao
Oct 31, 2017
  • Given , f(2x)= [ f ( x ) ] 2 [f(x)]^2

\implies f(x)= m x m^x

Where m is any constant

Given that , f(x)=1

\implies m x m^x =1

Therefore, x = 0 \boxed{x=0}

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