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I have a collection of nine movies which come from three different trilogies. How many distinct non-ordered groups of movies can I take from my collection such that no three movies come from the same trilogy?

Note: A group can have any whole number of movies.


The answer is 343.

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1 solution

Manuel Kahayon
Jul 10, 2016

Let the movies be a 1 , a 2 , a 3 , b 1 , b 2 , b 3 , c 1 , c 2 , c 3 a_1, a_2, a_3, b_1, b_2, b_3, c_1, c_2, c_3 where a , b , c a,b,c represent different trilogies.

For the group a 1 , a 2 , a 3 a_1, a_2, a_3 , we can make 8 8 distinct subsets, but one of them is not possible since it contains all 3 3 movies from the same trilogy, so we can make 7 7 possible subsets from here.

Similaly, there are also 7 7 subsets possible for b b and c c . We just multiply the number of possible subsets for the trilogies, i.e. 7 3 = 343 7^3 = \boxed{343} .

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