A rectangular garden has a length that is twice as long as its width. If the perimeter is 300, what is the area of the garden?
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Let P = 3 0 0 be the perimeter.
Let W be the width.
Let L be the length.
Let A be the area.
Given 2 P = W + L , A = W × L and L = 2 W ...
⟹ W + L = 1 5 0
⟹ L = 1 5 0 − W = 2 W
⟹ 3 W = 1 5 0
⟹ W = 5 0 ⟹ L = 1 0 0
⟹ A = 5 0 × 1 0 0 = 5 0 0 0
Thanks for the good clear solution.
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Let:
Since the formula for the perimeter of a rectangle is 2(length + width), we use it to find the length and width since the perimeter is already given.
2(2x + x) = 300
2(3x) = 300
6x = 300
x = 50
2x = 100
By substituting the value of x with the ones at the top, we will know that the width is 50 and the length is 100 since 2(50) is 100.
The question asks for the area of the garden and since we now have the width and length of the garden, we may now get the garden's area.
Formula for the area of a rectangle:
Area of rectangle = (Length)(Width)
Area of rectangle = (100)(50)
Area of rectangle = 5000
or you could also do it like this:
Area of rectangle = x(2x)
since ,as seen at the top, x is the width and 2x is the length
Area of rectangle = 2x^2
And after this, just substitute the value of x, which is 50, to the expression
Area of rectangle = 2(50)^2
Area of rectangle = 2(2500)
Area of rectangle = 5000
So the area of the rectangular garden is 5000