2 moles of He mixes with 2 g of Hydrogen at NTP. What is the specific heat capacity of the mixture at the constant pressure
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
He is a monoatomic gass and Hydrogen is a diatomic gas. For monoatomic gas we Know that, Cp = 5R/2 For diatomic gas we know that, Cp = 7R/2
Moles of He (n1) = 2 Moles of Hydrogen (n2) = (weight / Molecular weight) = (2 / 2) = 1 (Cp) mixture = (n1Cp1 + n2Cp2) / (n1 + n2) = (2 5R/2 + 1 7R/2) / (2 + 1) = 17R/6