GCD

Algebra Level 2

Find the greatest number which divides 2011 and 2623 leaving remainder 9 and 5 respectively

154 158 156 254

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1 solution

Richard Costen
Dec 5, 2016

A number that divides 2011 with remainder 9, will divide (2011-9)=2002 with no remainder. Similarly the same number will divide (2623-5)=2618. Thus the number is the GCD of 2002 & 2618. 2002 = 2 × 7 × 11 × 13 2618 = 2 × 7 × 11 × 17 the GCD is 2 × 7 × 11 = 154 2002=2\times 7\times 11\times 13 \\2618=2\times 7\times 11\times 17 \\ \therefore \text{ the GCD is }2\times 7\times 11=\boxed{154} or the Euclidean Algorithm can be used to find the GCD.

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