Generalizing Riemann Sums

Calculus Level 2

A function f ( x ) f(x) is differentiable for all x x over the interval [ a , b ] [a, b] where a , b Z a, b \in \mathbb{Z}

Approximating a b f ( x ) d x \displaystyle\int_{a}^{b}f(x)dx using a left Riemann sum with 1 unit subintervals is equivalent to evaluating which of the following?

A. a b f ( x ) d x \displaystyle\int_{a}^{b}\lfloor f(x) \rfloor dx

B. a b f ( x ) d x \displaystyle\int_{a}^{b}f(\lfloor x \rfloor)dx

C. a b f ( x ) d x \displaystyle\int_{a}^{b}\lceil f(x) \rceil dx

D. a b f ( x ) d x \displaystyle\int_{a}^{b}f(\lceil x \rceil)dx

Notation:

\lfloor \cdot \rfloor denotes the floor function .

\lceil \cdot \rceil denotes the ceiling function .

A C B D

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Braden Dean
Dec 27, 2020

Example function:

Notice that for all x ∉ Z x \not\in \mathbb{Z} , f ( x ) f(\lfloor x \rfloor) takes the value of the function at the greatest integer below it, or to the immediate left on a number line. This means that f ( x ) f(x) will intersect f ( x ) f(\lfloor x \rfloor) on the left of each piece of its graph. Effectively, f ( x ) f(\lfloor x \rfloor) just graphs the height of each of the rectangles used when evaluating a left Riemann sum with these constraints.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...