Let be a right triangle such that is the hypotenuse and the right angle point from on the hypotenuse. If . Find the value of when the perimeter equals 38.
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AB=c, BC=a, AC=b & CD=12
Hence ab=12c & a+b+c=38
a²+b²=c²
(a+b)²-2ab=c²
(38-c)²-24c=c²
1444-100c=0 or c=14.44