Geometrical Probability includes dice?

Given $a,b,c$ are determined by throwing a dice thrice then which of the following is/are correct?

$A)$ the probability that origin $(0,0)$ lies inside the circle $(x-a)^{2}+(y-b)^{2}=c^{2}$ is $\frac{1}{3}$

$B)$ the probability that origin $(0,0)$ lies inside the circle $(x-a)^{2}+(y-b)^{2}=c^{2}$ is $\frac{2}{9}$

$C)$ the probability that origin $(0,0)$ lies on the circle $(x-a)^{2}+(y-b)^{2}=c^{2}$ is $\frac{1}{108}$

$D)$ the probability that origin $(0,0)$ lies outside the circle $(x-a)^{2}+(y-b)^{2}=c^{2}$ is $\frac{82}{108}$

Clarification: We are using an unbiased 6-sided dice. The value of $a$ is determine on the numerical value of the top face of the dice thrown the first time; the value of $b$ is determine on the numerical value of the top face of the dice thrown the second time; the value of $c$ is determine on the numerical value of the top face of the dice thrown the third time.

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